Question

A particle is projected with a velocity $6\hat{i}+8\hat{j}$, $3m$ away from a vertical wall. After striking the wall it lands at .......... away from the wall

• A. $3m$
• B. $3.3m$
• C. $5.5m$
• D. $6.6m$

Answer 1

The correct option is D $6.6m$

Time of Flight$,T,$ is given by,
$T=\frac{2u_y}{a_y}=\frac{2\times 8}{10}=1.6$
Now again, we know that, $t$ is given by,
$t=\frac{diatance}{a_x}=\frac{3}{6}=0.5s$
Now, horizontal distance away from the wall, $x=u_x(T-t)=6(1.6-0.5)=6.6m$