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Question

A particle is projected with a velocity of 7 ms1 at an angle 60 with horizontal. Find the average velocity of the projectile between the instants of point of projection and reaching the highest point

A
2 m/s
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B
54 m/s
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C
74 m/s
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D
34 m/s
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Solution

The correct option is C 74 m/s
Given u=7 ms1, θ=60Average velocity=Total displacementtime
From the figure, Δr is the displacement of the particle.
vavg=rT2=H2+R24T2
But, HR=tanθ4 H=Rtanθ4vavg=R2tan2θ+16R24T2=R24T21+tan2θ4=2u2sinθcosθ2usinθ4+tan2θ4=u24cos2θ+sin2θ=u21+3cos2θ
On puting the values of u and θ in above equation, we get
vavg=721+3×14vavg=74 ms1

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