Question

A particle is projected with an initial speed of $20m/s$ at an angle of ${60}^0$ with the horizontal. What will the horizontal distance travelled by the particle in the first one second be?

• A. $10m$
• B. $2.67m$
• C. $2.24m$
• D. $12.4m$

Answer 1

The correct option is A $10m$

Horizontal velocity will be $u_x=ucos{60}^0=20\times \frac{1}{2}=10m/s$

As there is $no$ acceleration in the $horizontal$ direction so the distance traveled in horizontal will be $d=speed\times time=10\times 1=10m$