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Question

A particle is sliding down a frictionless hemispherical bowl. It passes the point A at t=0. At this instant of time, the horizontal component of its velocity is v. A bead Q of the same mass as P is ejected from A at t =0 along the horizontal string AB (see figure) with the speed v. Friction between the bead and the string may be neglected. Let tP and tQ be the respective time taken by P and Q to reach the point B. Then


A

tP<tQ

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B

tP=tQ

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C

tP>tQ

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D

All of these

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Solution

The correct option is A

tP<tQ


For particle P, motion between A and C will be an accelerated one while between C and B a retarded one. But in any case horizontal component of it’s velocity will be greater than or equal to v on the other hand in case of particle Q, it is always equal to v. horizontal displacement of both the particles are equal, so tP<tQ.


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