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Question

A particle is thrown horizontally with 20m/s from the top of a tower of height 20m(g=10m/s2). Angle with horizontal at which it will hit the ground is:-

A
30
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B
60
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C
53
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D
45
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Solution

The correct option is D 45
(D)
vx=ux=20
using: v2u2=2as to find vy
vy=2gh
vy=20
tanθ=vyvx
tanθ=20/20=1
θ=45o



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