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Question

A particle is thrown vertically upwards. Its velocity at half of the height is 10m/s, then the maximum height attained by it will be: (g = 10 m/s2).


A

10 m

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B

20 m

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C

15 m

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D

25 m

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Solution

The correct option is A

10 m


Step (1) Given:

The velocity at the half of the height, v=10m/s

The acceleration due to gravity, g=10m/s2

Step (2) Finding the equation of motion when the particle is at the half of the height:

Let the maximum height be h meter.

By the equation of motion formulas, we know

v2=u22gs

where v is final velocity, g is the acceleration due to gravity and s is displacement.

102=u22gh2100=u2gh(i)

Step (3) Finding the equation of motion when the particle is at the maximum height:

At the maximum height, v=0

0=u22ghu2=2gh..(ii)

Step (4) Finding the maximum height using the equations (i) & (ii):

Putting the value of u2 in equation (i) we get

100=2ghgh100=ghh=100g=10010=10m

Hence, the answer is (A) 10 m


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