A particle moves 3 m north, then 4 m east and finally 6 m south. Which of the following is correct about the distance travelled and the displacement?
The distance travelled is 13 m.
The displacement is 5 m.
Let the particle start from A and finally reached B as shown. Distance is the length of the actual path taken by it.
In this case, distance =3+4+6=13m
Displacement is the shortest distance between the initial and final position.
In this case, displacement =AB
=√(BC2+AC2) [Pythagoras Theorem]
=√(32+42)=5 m