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Question

A particle moves along a circle of radius (20π) m with constant tangential acceleration. If velocity of the particle is 80 m/s at the end of the 2nd revolution after the motion has begun, the tangential acceleration is

A
40 m/s2
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B
640 m/s2
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C
160 m/s2
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D
40π m/s2
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Solution

The correct option is A 40 m/s2
We know,
at=Rαω0=0θ=4π

We can use,
ω2=ω20+2αθ
ω2=0+2αθ

But, we know
ω=vR=8020/π=4π rad/s

(4π)2=2α4π
α=2π

at=Rα=20π×2π=40 m/s2

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