Question

# A particle moves along a parabolic path y=−9x2+6x in such a way that the x- component of velocity remains constant and has a value 13 m/s, then the y-component of velocity of the particle at t=1 s is

A
13 m/s
B
3 m/s
C
23 m/s
D
0 m/s

Solution

## The correct option is D 0 m/sdydt=−18xdxdt+6dxdt x=v.t=13t,dxdt=vx=13m/sdydt=−18xdxdt+6×13=−1813(13t)+2vy=dydt=−2t+2 At, t=1 s vy=−2×1+2=0 m/s

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