A particle moves along the parabolic path y=ax2 in such a way that the x component of the velocity remains constant, say c. The acceleration of the particle is
A
ac^k
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B
2ac2^j
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C
2ac2^k
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D
a2c^j
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Solution
The correct option is B2ac2^j y=ax2,dydt=a(2x)dxdt=2acx,d2ydt2=2acdxdt=2ac2