A particle moves along x−axis in such a way that its x− coordinate varies with time t(in s) according to the equation: x=(6−4t+6t2)m. The velocity of the particle will vary with time according to the graph
A
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B
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C
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D
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Solution
The correct option is A v=ddt(x)=−4+12tm/s When t=0s,v=−4m/s When v=0ms,12t=4 or t=412=13s Slope of v−t graph, =v2−v1t2−t1=0−(−4)13−0=12 (Positive slope) Thus, option (a) is the correct answer.