A particle moves from (1,0,3) to the point (−3,4,5), when a force →F=(^i+5^k) acts on it. Amount of work done in Joules is:
A
14
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B
10
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C
6
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D
15
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Solution
The correct option is A6 Force is given as →F=^i+5^k Displacement
of the particle →S=(−3^i+4^j+5^k)−(^i+3^k)=−4^i+4^j+2^k Work done W=→F.→S ∴W=(^i+5^k).(−4^i+4^j+2^k) ⟹W=(−4)(1)+(5)(2)=6J