Question

A particle moves from $A$ to $B$ diametrically opposite in a circle of radius $5m$ with a velocity $10m{s}^{-1}$. Find the average acceleration.

• A. zero
• B. $\frac{40}{\pi }m{s}^{-2}$
• C. $\frac{20}{\pi }m{s}^{-2}$
• D. none

Answer 1

The correct option is B $\frac{40}{\pi }m{s}^{-2}$

As particle moves to diametrically opposite position it's velocity is opposite to initial velocity. Hence change in velocity is 20 m/s. Time taken to reach opposite end is πR/V i.e. π/2.

Hence average acceleration( change in V/time) = 40/π

Hence option 'B"