A particle moves from position r-1 - 3 - - 2 - - 6 - to position r-2 - 14 - - 13 - - 9 k- under the action of force 4 - - - - 3 k- N- The work done by this force will be

The correct option is A 100 J D= 11î nbsp;+ 11ĵ + 15k̂ nbsp; F= 4î + ĵ +3k̂ W=FD= (11î + 11ĵ + 15k̂)(4î+ĵ+3k̂)= 44+11+45= 100J ...

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Third Law of Motion

A particle mo...

Question

A particle moves from position ${¯ r}_{1} = 3^i + 2^j - 6^j$ to position ${¯ r}_{2} = 14^i + 13^j + 9^k$ under the action of force $4^j +^j + 3^k N$ . The work done by this force will be

100 J

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50 J

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200 J

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75 J

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Solution

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Similar questions

_{1} = (3^i + 2^j - 6^k) m

_{2} = (14^i + 13^j + 9^k) m

(4^i +^j + 3^k) N

{\to r}_{1} = 3^i + 2^j - 6^k

{\to r}_{2} = 14^i + 13^j - 9^k

(4^i +^j + 3^k)

N

{\to r}_{1} = 3^i + 2^j - 6^k

{\to r}_{2} = 14^i + 13^j - 9^k

(4^i +^j + 3^k)

N

_{1} = 3^i + 2^j - 6^k

_{2} = 14^i + 13^j + 9^k

\to F = 4^i +^j + 3^k

_{1} = 3^i + 2^j - 6^k

_{2} = 14^i + 13^j + 9^k

4^i +^j + 3^k

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