Question

A particle moves in a circle of radius $1.0cm$ with a speed given by $v=2t$ where $v$ is in $cm/s$ and $t$ in seconds. Find the tangential acceleration at $t=1s$.

• A. $2.0m{s}^{-2}$
• B. $3.0m{s}^{-2}$
• C. $4.0m{s}^{-2}$
• D. $5.0m{s}^{-2}$

Answer 1

The correct option is A $2.0m{s}^{-2}$

Velocity of the particle, $v\left(t\right)=2t$ cm/s

$\therefore$ Tangential acceleration, $a_t=\frac{dv\left(t\right)}{dt}=\frac{d\left(2t\right)}{dt}=2$ $cm/s^2$