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Byju's Answer

Standard XII

Physics

Conservation of Momentum

A particle mo...

Question

A particle moves in the x-y plane under the action of a force $\to F = - 2 k s i n k t (^i +^j)$ at any time t its linear

momentum is given by P_X = 2cos (kt) and P_Y = 2cos (kt)The angle between $\to F a n d \to P$ at time t is

0⁰

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30⁰

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90⁰

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180⁰

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Solution

The correct option is D
180⁰

$\to P = 2 c o s k t (^i +^j) \to F = - 2 k s i n k t (^i +^j) Angle between \to F a n d \to P = 180^{0}$

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Similar questions

Q. A particle moves in the

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Q. A particle moves in the

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A particle moves in the x-y plane under the action of a force F such that the value of its linear momentum $(\to P)$ at any time 't' is $P_{x} = 2 c o s t, P_{y} = 2 s i n t$ .The angle $θ$ between $\to F$ and $\to P$ at a given time t. will be

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such that the values of linear momentum

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and

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A

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A particle moves in the x-y plane under the action of a force →F=−2k sin kt(^i+^j) at any time t its linear momentum is given by PX = 2cos (kt) and PY = 2cos (kt)The angle between →Fand→P at time t is

The correct option is D 1800 →P=2coskt(^i+^j)→F=−2k sin kt(^i+^j)Angle between→Fand→P=1800

A particle moves in the x-y plane under the action of a force $\to F = - 2 k s i n k t (^i +^j)$ at any time t its linear

momentum is given by P_X = 2cos (kt) and P_Y = 2cos (kt)The angle between $\to F a n d \to P$ at time t is

The correct option is D
180⁰

$\to P = 2 c o s k t (^i +^j) \to F = - 2 k s i n k t (^i +^j) Angle between \to F a n d \to P = 180^{0}$