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Byju's Answer

Standard XII

Physics

Law of Conservation of Mechanical Energy

A particle mo...

Question

A particle moves in X-Y plane under the action of forces $F$ such that the values of linear momentum $p$ at any times is $p_{x} = 2 cos t$ and $p_{y} = 2 sin t$ . The angle between $\to F$ and $\to p$ at the time $t$ will be:

0^{o}

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30^{o}

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90^{o}

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180^{o}

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Solution

The correct option is C $90^{o}$
$F_{x} = d p_{x} / d t = - 2 s i n t$ and $F_{y} = d p_{y} / d t = 2 c o s t$
so angle between $\to F$ and $\to p$ will be $90^{0}$ because we see that their $d o t$ product is $z e r o$ .

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