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Question

A particle moves rectilinearly possessing a parabolic st graph. Find the average velocity of the particle over a time interval from t=12 s to t=1.5 s.
981461_6e65403557734403b73b992f04acaa8c.png

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Solution

First we know the equation of motion of the particle will be s=atbt2
Now, from the figure we know that parabola is symmetric above t=1
Or, dsdt=0,at t=1
so we get, a2bt=0 or a=2b........(1)
Using (1)
s0.5=a(0.5)b(0.5)2=3a8 and s1.5=a(1.5)b(1.5)2=3a8
So there is no displacement between t=0.5 and t=1.5
hence the vavg=displacementtime =01.50.5=0

1710264_981461_ans_babe3d177370430980756ee2715a40be.JPG

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