A particle moves under the action of a force F -2 - along a line y - x -1- If work done by the force along the path is zero- then - isA- 2B- 3C- 4D- 4 -3

The correct option is A 2W = F⃗. dr = (αî nbsp;+ 2 ĵ).(dx î + dy ĵ) W = α dx + 2 dy = 0 α dx = 2dy dy/dx = α/2 Given y + x = 1 dy/dx = 1 On comparing ...

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Byju's Answer

Standard XII

Physics

Angular Analogue of Linear Momentum

A particle mo...

Question

A particle moves under the action of a force $\to F = α^i + 2^j$ along a line y + x = 1. If work done by the force along the path is zero, then $α$ is

2

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4

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4 \sqrt{3}

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Solution

The correct option is A $2$
$W = \to F . \to d r = (α^i + 2^j) . (d x^i + d y^j) W = α d x + 2 d y = 0 α d x = - 2 d y \frac{d y}{d x} = \frac{- α}{2} G i v e n y + x = 1 \frac{d y}{d x} = - 1$
On comparing, we get
$- \frac{α}{2} = - 1 \Rightarrow α = 2$

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A particle moves under the action of a force →F=α^i+2^j along a line y + x = 1. If work done by the force along the path is zero, then α is

The correct option is A 2W=→F.→dr=(α^i+2^j).(dx^i+dy^j)W=αdx+2dy=0αdx=−2dydydx=−α2Giveny+x=1dydx=−1 On comparing, we get −α2 = −1⇒α = 2

A particle moves under the action of a force $\to F = α^i + 2^j$ along a line y + x = 1. If work done by the force along the path is zero, then $α$ is

The correct option is A $2$
$W = \to F . \to d r = (α^i + 2^j) . (d x^i + d y^j) W = α d x + 2 d y = 0 α d x = - 2 d y \frac{d y}{d x} = \frac{- α}{2} G i v e n y + x = 1 \frac{d y}{d x} = - 1$
On comparing, we get
$- \frac{α}{2} = - 1 \Rightarrow α = 2$