Question

A particle moves with constant speed $v$ along a regular hexagon $ABCDEF$ in the same order. Then the magnitude of the average velocity for its motion from $A$ to

• A. $F$ is $v/5$
• B. $D$ is $v/3$
• C. $C$ is $v\sqrt{3}/2$
• D. $B$ is $v$

Answer 1

The correct option is A $F$ is $v/5$

Let the side be of length of a. In going from A to F along ABCDEF, time taken = $\frac{5a}{v}$

Displacement from A to F = a

$\therefore$ Average velocity from A to F = $\frac{v}{5}$