Question

A particle moves with constant speed $v$ along a regular hexagon ABCDEF in the same order. Then the magnitude of the velocity for its motion from A to

• A. F is $\frac{v}{5}$
• B. D is $\frac{v}{3}$
• C. C is $\frac{v\sqrt{3}}{2}$
• D. B is $v$

Answer 1

Answer: (A), (C), (D)

F is $\frac{v}{5}$
C is $\frac{v\sqrt{3}}{2}$
B is $v$

Let side length be 'a' From A to B
For A to B:$\overrightarrow{V}=\frac{displacement}{time}$

$\Rightarrow \frac{a}{\frac{a}{V}}=V$
For A to C:$\overrightarrow{V}=\frac{2aSin60}{\frac{2a}{V}}=\frac{\sqrt{3}}{2}V$
For A to D:$\overrightarrow{V}=\frac{2a}{\frac{3a}{V}}=\frac{2}{3}V$
For A to F:$\overrightarrow{V}=\frac{a}{\frac{5a}{V}}=\frac{1}{5}V$