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Question

A particle moving along x−axis whose position is given by x=4−9t+t33 then choose the correct statement(s) for this motion-

A
Direction of motion is not changing at any of the instants
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B
For 0<t<3s, the particle is slowing down
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C
Direction of motion is changing at t=3sec
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D
For 0<t<3s the particle is speeding up
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Solution

The correct options are
B For 0<t<3s, the particle is slowing down
D Direction of motion is changing at t=3sec

x=49t+t33v=dxdt=(9+t2) and a=(dvdt)=2t . Therefore (v<0)

For period 0<t<3s a.v <0 for period 0<t<3s


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