1
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Question

# A particle moving eastwards with 5 ms−1. In 10 s the velocity changes to 5 ms−1 northwards. The average acceleration in this time is

A
12 m/s2 North-East.
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B
12 m/s2 North-West.
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C
12 m/s2 North-West.
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D
Zero.
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Solution

## The correct option is C 1√2 m/s2 North-West.Considering eastwards as positive x−axis and northwards as positive y−axis, we can write the velocities as per the question as initial velocity of the particle →vi=5^i and the final velocity of the particle →vf=5^j So, average acceleration is given as −→aav=→vf−→vit=5^j−5^i10=12(^j−^i) or, |−→aav|=1√2 m/s2 North-West.

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