A particle moving in one dimension with a constant acceleration of $2 m / s^{2}$ is observed to cover a distance of $5 m$ during a particular interval of $1 s$ . The distance covered by the particle in the next $1 s$ interval is in metre

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Solution

The correct option is C $7$
The distance cover 5 m in time interval 1 s means its speed is $5 m / s$ .
Using, $v = a t$ , $t = v / a = 5 / 2 s$
For next interval, $t_{1} = t + 1 = 5 / 2 + 1 = 7 / 2 s$
For after time $t_{1}$ , the speed will be $v_{1} = a t_{1} = 2 (7 / 2) = 7 m / s$
Thus, distance covered by next 1 s interval will be $7 m$ .

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A particle moving in one dimension with a constant acceleration of 2m/s2 is observed to cover a distance of 5m during a particular interval of 1s. The distance covered by the particle in the next 1s interval is in metre

The correct option is C 7The distance cover 5 m in time interval 1 s means its speed is 5m/s.Using, v=at, t=v/a=5/2sFor next interval, t1=t+1=5/2+1=7/2sFor after time t1, the speed will be v1=at1=2(7/2)=7m/sThus, distance covered by next 1 s interval will be 7m.

A particle moving in one dimension with a constant acceleration of $2 m / s^{2}$ is observed to cover a distance of $5 m$ during a particular interval of $1 s$ . The distance covered by the particle in the next $1 s$ interval is in metre