A particle of mass 0-3 kg is subjected to a force F - kx with k -15 N - m- What will be the magnitude of its initial acceleration in - m - s 2- released from a point x -20 cm from its equilibrium position-A- 10B- 5C- 20D- 15

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Question

A particle of mass $0.3 k g$ is subjected to a force $F = - k x$ with $k = 15 \frac{N}{m}$ . What will be the magnitude of its initial acceleration (in $\frac{m}{s^{2}}$ ), if it is released from a point $x = 20 c m$ from its equilibrium position?

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Solution

The correct option is A $10$
Assuming the direction of compression as negative,

$F = - k x = m a \Rightarrow a = \frac{- 15 (0.2)}{0.3} = - 10 m / s^{2}$

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. What will be the magnitude of its initial acceleration (

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A particle of mass 0.3 kg is subjected to a force F=−kx with k=15 Nm. What will be the magnitude of its initial acceleration (in ms2), if it is released from a point x=20 cm from its equilibrium position?

The correct option is A 10Assuming the direction of compression as negative, F=−kx=ma⇒a=−15(0.2)0.3=−10 m/s2

A particle of mass $0.3 k g$ is subjected to a force $F = - k x$ with $k = 15 \frac{N}{m}$ . What will be the magnitude of its initial acceleration (in $\frac{m}{s^{2}}$ ), if it is released from a point $x = 20 c m$ from its equilibrium position?

The correct option is A $10$
Assuming the direction of compression as negative,

$F = - k x = m a \Rightarrow a = \frac{- 15 (0.2)}{0.3} = - 10 m / s^{2}$