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Question

A particle of mass 10 kg is dropped from tower of height 10 m. Find the ratio of workdone by gravity from point ′A′ to ′B′ and change in potential energy from ′A′ to ′B′

A
1
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B
1
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C
2
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D
16
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Solution

The correct option is B 1
Work done by force of gravity from A to B, WAB=(mg)h=mgh ...(i)
(Positve because force & displacement are in the same direction)

Change in potential energy from point A to B,
UAB=UBUA ...(ii)
=mg(10h)mg(10)
(calculating from ground as a reference)
=mgh
WABUAB=mghmgh=1

Hence option B is the correct answer

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