wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass 2 kg performing of SHM and its potential energy function is given as U=4x2−20x. If maximum potential energy is 75 J then:
The equilibrium position of a particle is -

A
x=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=2.5 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x=5 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Join BYJU'S Learning Program
CrossIcon