A particle of mass 2kg is moving in xy plane. Its velocity and acceleration at a certain instant of time is given by →v=(3^i+4^j)m/s and →a=(5^i+4^j)m/s2. Find the power delivered by force at that instant of time.
A
60W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
62W
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
64W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
66W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B62W Given: Mass of particle, m=2kg Instantaneous velocity, →v=(3^i+4^j)m/s Instantaneous acceleration, →a=(5^i+4^j)m/s2 We know that the instantaneous power of a force is given by, P=→F.→v ⇒P=m→a.→v ⇒P=2×(5^i+4^j).(3^i+4^j) ⇒P=30+32=62W