A particle of mass M and charge Q moving with velocity v describes a circular path of radius R when subjected to a uniform transverse by the field of induction B. The work done by the field, when the particle completes one full circle, is :
A
(Mv2R)2πR
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B
Zero
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C
BQ2πR
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D
BQv2πR
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Solution
The correct option is B Zero When a charged particle describes a circular path in a uniform magnetic field, the charged particle experiences a magnetic force towards the center of circular path, according to Fleming's left hand rule. Therefore the magnetic force and velocity (tangent to circular path) are perpendicular to each other during the circular motion. As the direction of displacement, is the direction of velocity, hence force and displacement are perpendicular to each other.