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Question

A particle of mass M and charge Q moving with velocity v describe a circular path of radius R when subjected to a uniform transverse magnetic field of induction B. The work done by the field when the particle completes one full circle is:

A
(Mv2R)2πR
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B
zero
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C
BQ2πR
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D
BQv2πR
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Solution

The correct option is B zero
Force= F=Q(ν×B)
Work done= W=Fdr
=Q(ν×B)dr
=0 [Angle between (ν×B) and dr is π/2]

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