A particle of mass ′m′ and ′→v′ collides oblique elastically with a stationary particle of mass ′m′. The angle between the velocity vectors of the two particles after the collision is
A
45∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
90∘
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A90∘ Collision is elastic hence velocities along the line of impact will be exchanged.
Velocity of particle along the line of impact V=vcosθ
velocity of disc =v√32
so the particle will move perpendicularly.