You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Projectile Time, Height and Range

A particle of...

Question

A particle of mass $m$ is attached to a light string of length $l$ , the other end of which is fixed. Initially the string is kept horizontal and then particle is given an upward velocity $v$ so that it is just able to complete the circle. Then:

the string becomes slack when the particle reaches the highest point.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

the velocity of the particle becomes zero at the highest point.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the KE of the ball at highest position was

\frac{1}{2} m v^{2} = m g l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

the particle again passes through initial position

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A the string becomes slack when the particle reaches the highest point.
D the particle again passes through initial position
If the particle need to complete the whole circle.It should be just taut at top most point.and it would come to the starting point as no energy is lost in the path.
So, options A,D are correct.

Suggest Corrections

Similar questions

Q. A particle of mass m is attached to a light string of length l, the other end of which is fixed. Initially the string is kept horizontal and the particle is given an upward velocity v. The particle is just able to complete a circle.
(a) The string becomes slack when the particle reaches its highest point.
(b) The velocity of the particle become zero at the highest point.
(c) The kinetic energy of the ball in initial position was

\frac{1}{2} m v^{2} = m g l

(d) The particle again passes through the initial position.

A particle of mass m is attached to a light string of length l, the other end of which is fixed. Initially the string is kept horizontal and the particle is given an upward velocity v. The particle is just able to complete a circle.

Q. A particle is suspended from a fixed point by a string of length

5 m

. It is projected from the equilibrium position with such a velocity that the string becomes slack after the particle has reached a height of

8 m

above the lowest point. Find the velocity of the particle, just before the string becomes slack.(take

g = 10 {m/s}^{2}

)

Q. A particle of mass m is tied to a light string of length l and rotated along a vertical circular path. What should be the minimum speed at a highest point of its path so that the string does not become slack at any position?

Q. A particle is moving in a circular path in the vertical plane. It is attached at one end of a string of length

l

whose other end is fixed. The velocity at lowest point is

u

. The tension in the string is

\to T

and acceleration of the particle is

\to a

at any position. Then

\to T . \to a

is zero at highest point if

Join BYJU'S Learning Program

A particle of mass m is attached to a light string of length l, the other end of which is fixed. Initially the string is kept horizontal and then particle is given an upward velocity v so that it is just able to complete the circle. Then:

A particle of mass $m$ is attached to a light string of length $l$ , the other end of which is fixed. Initially the string is kept horizontal and then particle is given an upward velocity $v$ so that it is just able to complete the circle. Then: