You visited us 1 times! Enjoying our articles? Unlock Full Access!

Newton's Laws of Motion

A particle of...

Question

A particle of mass $m$ is moving with a constant acceleration $2 a$ towards another particle of mass $4 m$ as shown in figure. Mass $4 m$ is also moving with acceleration $a$ towards the particle of mass $m$ . Find the acceleration of $C O M$ of the system.

a / 5

(towards left)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 a / 5

(towards left)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a / 5

(towards right)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 a / 5

(towards right)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 a / 5$ (towards left)
As we know,
$a_{C O M} = \frac{m_{1} a_{1} + m_{2} a_{2}}{m_{1} + m_{2}}$
$= \frac{m (2 a) + 4 m (- a)}{m + 4 m}$
(consider rightward direction as +ve)
$\Rightarrow a_{C O M} = \frac{2 m a - 4 m a}{5 m a} = \frac{- 2 a}{5}$
Hence, acceleration of $C O M$ of the system will be $\frac{2 a}{5}$ towards left

Suggest Corrections

Similar questions

Q. A particle of mass

m

is moving with a constant acceleration

2 a

towards another particle of mass

4 m

as shown in figure. Mass

4 m

is also moving with acceleration

a

towards the particle of mass

m

. Find the acceleration of

C O M

of the system.

A particle of mass m moving towards west with a speed v collides with another particle of mass m moving towards south. If two particles stick to each other the speed of the new particle of mass 2m will be?

Q. (i) A particle of mass m is moving in a circular orbit of radius r with a uniform speed v: Find:
(1) The acceleration of the particle towards the center of the circular path,

Q. A particle of mass m moving towards East with a velocity v collides with another particle of same mass moving towards North with the same speed and adheres to it. The velocity of the combined particle is

Q. A particle of mass

m

moving with speed

v

towards east strikes another particle of same mass moving with same speed

v

towards the north. After striking, the two particle fuse together. Determine the speed this new particle of mass

2 m

will move in north-east direction?

Join BYJU'S Learning Program

Explore more

Newton's Laws of Motion

Standard XIII Physics

Join BYJU'S Learning Program

A particle of mass m is moving with a constant acceleration 2a towards another particle of mass 4m as shown in figure. Mass 4m is also moving with acceleration a towards the particle of mass m. Find the acceleration of COM of the system.

The correct option is B 2a/5 (towards left)As we know, aCOM=m1a1+m2a2m1+m2 =m(2a)+4m(−a)m+4m (consider rightward direction as +ve) ⇒aCOM=2ma−4ma5ma=−2a5 Hence, acceleration of COM of the system will be 2a5 towards left

A particle of mass $m$ is moving with a constant acceleration $2 a$ towards another particle of mass $4 m$ as shown in figure. Mass $4 m$ is also moving with acceleration $a$ towards the particle of mass $m$ . Find the acceleration of $C O M$ of the system.