A particle of mass $m$ moving with velocity $v$ collides with a stationary particle of mass $2 m$ . Then the speed of the system after collision is:

2 v

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\frac{v}{2}

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3 v

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\frac{v}{3}

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Solution

The correct option is D $\frac{v}{3}$
Mass of first particle is $m_{1} = m$ and its velocity before collision $u_{1} = v$

Mass of second particle is $m_{2} = 2 m$ and its velocity before collision $u_{2} = 0$

Let the velocity of combined system just after collision be $V$ .

Using conservation of linear momentum :

$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) V$

$∴ (m) (v) + (2 m) (0) = (m + 2 m) V$

$⟹$ $V = \frac{v}{3}$

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