A particle of mass M and charge Q moving with velocity →V describes a circular path of radius R when subjected to a uniform transverse magnetic field of induction B. The work done by the field when the particle completes one full circle is
A
(Mv2R)2πR
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B
zero
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C
B2πR
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D
Bv2πR
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Solution
The correct option is B zero Since the particle completes one full circle, therefore displacement of particle =0 Work done = force × displacement =0