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Question

A particle projected from the level ground just clears in it's ascent a wall 30m high and 1203 away measured horizontally. The time since projection to clear the wall is two second. It will strike the ground in the same horizontal plane from the wall on the other side at a distance of

A
1503m
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B
1803m
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C
1203m
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D
2103m
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Solution

The correct option is A 1803m
Sy=ut12gt230=(usinθ)(2)2gusinθ=25
Sx=ucosθt2ucosθ=1203
Range =u2sin2θg=(ucosθ)(usinθ)2g
=(603)×25×210=3003
Hence, distance from wall =30031203
=1803 m

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