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Question

# A particle projected from the level ground just clears in it's ascent a wall 30m high and 120√3 away measured horizontally. The time since projection to clear the wall is two second. It will strike the ground in the same horizontal plane from the wall on the other side at a distance of

A
1503m
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B
1803m
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C
1203m
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D
2103m
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Solution

## The correct option is A 180√3mSy=ut−12gt2⇒30=(usinθ)(2)−2g⇒usinθ=25Sx=ucosθt⇒2ucosθ=120√3Range =u2sin2θg=(ucosθ)(usinθ)2g =(60√3)×25×210=300√3Hence, distance from wall =300√3−120√3 =180√3 m

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