A particle reaches its highest point when it has covered exactly one half of its horizontal range. The corresponding point on the displacement time graph is characterised by

Negative slope and zero curvature

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Zero slope and negative curvature

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Zero slope and positive curvature

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Positive slope and zero curvature

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Solution

The correct option is B Zero slope and negative curvature

Zero slope and negative curvature

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\begin{matrix} Table-1 & Table-2 (A) Velocity - time graph & (P) Slope \to negative (B) Acceleration - time graph & (Q) Slope \to positive (C) Displacement - time graph & (R) Slope \to zero (S) | Slope | \to increasing (T) | Slope | \to decreasing (U) | Slope | \to constant \end{matrix}

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