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Question

A particle returns to the starting point after 10 s. if the rate of change of velocity during the motion is constant, then its location after 7 s will be same as that after
  1. 4 s
  2. 3 s
  3. 5 s
  4. 6 s


Solution

The correct option is B 3 s
As the particle returns to its starting position after 10 s, we can say
0=u(10)12a(10)2 (By second equation of motion)
ua=5
Distance at which the particle will change its direction of motion is given by
0=uat
t=ua
t=5 s

Location of the particle at (t=7 s) = Location of the particle at (t=3 s)

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