A particle starts from a point A and travels along the sold curve shown in figure. Find approximaterly the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B

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Solution

At position B instantaneous velocity has direction along $\to A B$

For average velocity between A and B

$V_{a v} = \frac{displacement}{time}$

= $(\frac{\to A B}{t})$

We can see that $\to A B$ is alont $\to B C$ i,e. they are in same direction. The point is B (5 m, 3 m).

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A particle starts from a point A and travels along the sold curve shown in figure. Find approximaterly the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B

At position B instantaneous velocity has direction along →AB For average velocity between A and B Vav=displacementtime = (→ABt) We can see that →AB is alont →BC i,e. they are in same direction. The point is B (5 m, 3 m).

At position B instantaneous velocity has direction along $\to A B$

For average velocity between A and B

$V_{a v} = \frac{displacement}{time}$

= $(\frac{\to A B}{t})$

We can see that $\to A B$ is alont $\to B C$ i,e. they are in same direction. The point is B (5 m, 3 m).