A particle starts from a point A and travels along the solid curve shown in figure. Find approximately the position B of the particle such that the average velocity between the position A and B has the same direction as the instantaneous velocity at B.
A
x=5m,y=3m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x=3m,y=2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x=6m,y=2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x=5m,y=2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Bx=5m,y=3m
At B (x=5m,y=3m) the curve changes direction rapidly. During the change of direction of velocity, at an instance, it is same as the line joining AB.