A particle starts from a point with a velocity of $+ 6 m/s$ and moves with an acceleration of $- 2 {m/s}^{2}$ . After what time will the particle be at the starting point?

2 s

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6 s

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4 s

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5 s

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Solution

The correct option is B $6 s$
We know that,

$s = u t + \frac{1}{2} a t^{2}$

$\Rightarrow 0 = 6 t + \frac{1}{2} (- 2) t^{2}$

$\Rightarrow 6 t - t^{2} = 0$

$\Rightarrow t (6 - t) = 0$

$∴ t = 6 s$

Hence, after $6 s$ particle will be at the starting point.

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A particle starts from a point with a velocity of +6 m/s and moves with an acceleration of −2 m/s2. After what time will the particle be at the starting point?

The correct option is B 6 sWe know that, s=ut+12at2 ⇒0=6t+12(−2)t2 ⇒6t−t2=0 ⇒t(6−t)=0 ∴t=6 s Hence, after 6 s particle will be at the starting point.

A particle starts from a point with a velocity of $+ 6 m/s$ and moves with an acceleration of $- 2 {m/s}^{2}$ . After what time will the particle be at the starting point?

The correct option is B $6 s$
We know that,

$s = u t + \frac{1}{2} a t^{2}$

$\Rightarrow 0 = 6 t + \frac{1}{2} (- 2) t^{2}$

$\Rightarrow 6 t - t^{2} = 0$

$\Rightarrow t (6 - t) = 0$

$∴ t = 6 s$

Hence, after $6 s$ particle will be at the starting point.