A particle starts from rest. Its acceleration (a) versus time (t) graph is as shown in the figure. The maximum speed of the particle will be
A
11 m/s
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B
55 m/s
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C
550 m/s
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D
66 m/s
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Solution
The correct option is B 55 m/s Acceleration is + ve till it becomes zero. Thus velocity is maximum at t = 11s Area under a - t graph = change in velocity 12×11×10=v−0 ⇒v=55ms−1