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Question

A particle starts from rest. Its acceleration (A) versus time (t) is as shown in the figure. The maximum speed of the particle will be

A
110 m/s
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B
55 m/s
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C
550 m/s
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D
660 m/s
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Solution

The correct option is B 55 m/s

The area under acceleration time graph gives change in velocity. As acceleration is zero at the end of 11 s
i.e. vmax = Area of ΔOAB
= 12 × 11 × 10 = 55 m/s

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