A particle starts from rest. Its acceleration (A) versus time (t) is as shown in the figure. The maximum speed of the particle will be
A
110m/s
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B
55m/s
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C
550m/s
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D
660m/s
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Solution
The correct option is B55m/s
The area under acceleration time graph gives change in velocity. As acceleration is zero at the end of 11s i.e.vmax=AreaofΔOAB =12×11×10=55m/s