Question

A particle starts from rest with a uniform acceleration, It travels a distance X is first two second & a distance y in the next two seconds.Then:-

• A. Y = x
• B. Y = 2x
• C. Y = 3x
• D. Y = 4 x

Answer 1

The correct option is C Y = 3x

$\begin{array}{c}\text{Correct option is (c)}\\ \text{Let acceleration = a}\\ \text{As we know,}\\ \text{distance in first two seconds}\\ \begin{array}{c}{s}_2=vt+\frac{1}{2}a{t}^2\\ s_2=\frac{1}{2}xa\times (2{)}^2\end{array}\\ s_2=2a=x\end{array}$

$\begin{array}{c}\text{distance in next two seconds =}\\ \begin{array}{cc}y& =s_4-s_2\\ & =\frac{1}{2}xax(4{)}^2-2a\\ \frac{y}{y}& =8a-2a\\ \text{so,}y& =3x\end{array}\end{array}$