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Question

# A particle starts from the origin at t=0 with an initial velocity of 3.0^i m/s and moves in the x−y plane with a constant acceleration (6.0^i+4.0^j) m/s2. The x−coordinate of the particle at the instant when its y−coordinate is 32 m is D meters. The value of D is:

A
32
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B
50
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C
60
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D
40
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Solution

## The correct option is C 60Given, →u=(3^i+0^j) m/s and →a=(6^i+4^j) m/s2 Using, s=ut+12at2, for y−axis y=uyt+12ayt2 ⇒32=0×t+12(4)t2 ⇒12×4×t2=32 ⇒t=4 s For x-axis, x=uxt+12axt2 ⇒x=3×4+12×6×42=60 m ∴D=60 Hence, (C) is the correct answer.

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