A particle starts from the point (0,8)m and moves with uniform velocity of 3ˆim/sec. After 5sec, the angular velocity of the particle about the origin will be
A
8289rad/sec
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B
38rad/sec
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C
24289rad/sec
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D
817rad/sec
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Solution
The correct option is C24289rad/sec The unit vector ^i is along the X-axis. Hence the velocity is along the X-axis. Distance covered in 5secs=v×t=3×5=15m r=√82+152=√289=17m
vsinθ is the velocity vector about the origin. Hence, ω=vsinθr=317×817=24289rad/sec