A particle starts from the point (0m,8m) and moves with uniform velocity of 3^im/s. After 5 seconds, the angular velocity of the particle about the origin will be :
A
8289rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
38rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
24289rad/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
817rad/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C24289rad/s
ω=V⊥r ω=3cosθr ω=3r×8r=24r2 In ΔOAB r2=(15)2+(8)2=289 ω=24289rad/s