A particle starts with some initial velocity and covers x1 distance with a1 acceleration and further x2 distance with a2 acceleration. If the final velocity is same as initial velocity then
A
a1=−a2
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B
a1x2=a2x1
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C
a1x1+a2x2=0
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D
a1x1+a2x2=0
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Solution
The correct option is Ca1x1+a2x2=0
Let the initial velocity be vo
For x1,v2=u2+2as ⇒v21=v2o+2a1x1(1)
and for x2,v2=u2+2as v2o=v21+2a2x2(2)
From (1) and (2), ⇒a1x1+a2x2=0