A particle with charge 2μC, moving with velocity 2×106m/s, enters normally in a magnetic field of 4T. The force experienced by the particle is?
A
4 N
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B
8 N
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C
12 N
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D
16 N
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Solution
The correct option is D 16 N Magnitude of the force experienced by a charge particle in a magnetic field is given by the formula: F=qvBsinθ θ=900 ⇒F=2×10−6×2×106×4 ⇒F=16N